User LoginArthur, ND, USA
Latitude and longitude coordinates are: 47.104141, -97.218140.
Established in 1880s, the town of Arthur is situated in North Dakota, about 18 miles north west of Fargo city. The settlement was initially named Rosedale, however, shorty it was renamed after C.A.Arthur, the 21st President of the country. The town was developing pretty slowly, and since it is situated quite far from Interstates and highways, it is rather the town for retired couples. The population of modern Arthur is only 400 people.
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Satellite Map of Arthur, ND, USA
Arthur, ND, USA Lat Long Coordinates Info
The latitude of Arthur, ND, USA is 47.104141, and the longitude is -97.218140. Arthur, ND, USA is located at United States country in the Towns place category with the gps coordinates of 47° 6' 14.9076'' N and 97° 13' 5.3040'' W.
| Country | United States |
|---|---|
| Latitude | 47.104141 |
| Longitude | -97.218140 |
| DMS Lat | 47° 6' 14.9076'' N |
| DMS Long | 97° 13' 5.3040'' W |
| UTM Easting | 635,201.92 |
| UTM Northing | 5,218,277.43 |
| Category | Towns |
| Country Code | US |
| Zoom Level | 9 |
Coordinates of Arthur, ND, USA is given above in both decimal degrees and DMS (degrees, minutes and seconds) format. The country code given is in the ISO2 format.
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